How do you write $f (x) = - 3 x^{2} + 3 x - 2$ $f(x) = -3x^2 + 3x - 2$ in vertex form?

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How do you write $f (x) = - 3 x^{2} + 3 x - 2$ $f(x) = -3x^2 + 3x - 2$ in vertex form?

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Answer 1 · 2016-07-26T16:45:15

f(x) = -3(x - 1/2)^2 - 5/4

Explanation:

First find the coordinate of the vertex>
x-coordinate of vertex:
$x = - \frac{b}{2 a} = - \frac{3}{- 6} = \frac{1}{2}$ $x = -b/(2a) = -3/-6 = 1/2$
y-coordinate of vertex:
$y (\frac{1}{2}) = - 3 (\frac{1}{4}) + 3 (\frac{1}{2}) - 2 = - \frac{3}{4} + \frac{3}{2} - 2 = - \frac{5}{4}$ $y(1/2) = -3(1/4) + 3(1/2) - 2 = -3/4 + 3/2 - 2 = -5/4$
Vertex form of y:
$f (x) = - 3 {(x - \frac{1}{2})}^{2} - \frac{5}{4}$ $f(x) = -3(x - 1/2)^2 - 5/4$

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How do you write $f (x) = - 3 x^{2} + 3 x - 2$ $f(x) = -3x^2 + 3x - 2$ in vertex form?

1 Answer

Explanation:

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