How do you write $f (x) = 3 x^{2} - 6 x + 9$ $f(x) = 3x^2 - 6x + 9$ into vertex form?

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How do you write $f (x) = 3 x^{2} - 6 x + 9$ $f(x) = 3x^2 - 6x + 9$ into vertex form?

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Answer 1 · 2017-07-23T00:07:58

$y = 3 {(x - 1)}^{2} + 6$ $y = 3(x - 1)^2 + 6$

Explanation:

x-coordinate of vertex:
$x = - \frac{b}{2 a} = \frac{6}{6} = 1$ $x = -b/(2a) = 6/6 = 1$
y-coordinate of vertex:
y (1) = 3 - 6 + 9 = 6
Vertex (1, 6)
Vertex form
$y = 3 {(x - 1)}^{2} + 6$ $y = 3(x - 1)^2 + 6$

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How do you write $f (x) = 3 x^{2} - 6 x + 9$ $f(x) = 3x^2 - 6x + 9$ into vertex form?

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Explanation:

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How do you write f(x)=3x2−6x+9f(x) = 3x^2 - 6x + 9 into vertex form?

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Explanation:

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How do you write $f (x) = 3 x^{2} - 6 x + 9$ $f(x) = 3x^2 - 6x + 9$ into vertex form?