How do you write $f(x)=4x^2-12x+5$ in factored form?

Question

5444 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-09-14T00:12:43

$f(x) = (2x - 5) (2x - 1)$

$f(x) = 4x^2 - 12x + 5$

$f(x) = ((4x - 10) (4x - 2)) /4$

$4 * 5 = 20$

You want factors of 20 that add to 12.

$f(x) = (cancel(2)(2x - 5) cancel(2)(2x - 1))/cancel(4)$

$f(x) = (2x - 5) (2x - 1)$

How do you write f(x)=4x^2-12x+5f(x)=4x^2-12x+5 in factored form?