How do you write $f(x) = 4x^2 +28x +45$ in vertex form?

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Answer 1 · 2016-03-27T11:20:45

$f(x)=4(x+7/2)^2-4$

$f(x)=4x^2+28x+45 or f(x)=4(x^2+7x+(7/2)^2)-49+45 or f(x)=4(x+7/2)^2-4$ Here vertex is at $(-7/2,-4)$ graph{(x+7/2)^2-4 [-10, 10, -5, 5]} [ans]

How do you write f(x) = 4x^2 +28x +45f(x) = 4x^2 +28x +45 in vertex form?