How do you write $f (x) = - 6 x^{2} - 5 x + 1$ $f(x)=-6x^2-5x+1$ in vertex form?

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How do you write $f (x) = - 6 x^{2} - 5 x + 1$ $f(x)=-6x^2-5x+1$ in vertex form?

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Answer 1 · 2017-04-24T08:21:09

$y = - 6 {(x + \frac{5}{12})}^{2} + \frac{49}{24}$ $y=-6(x+5/12)^2+49/24$

Explanation:

Vertex form is $f (x) = a {(x - h)}^{2} + k$ $f(x)=a(x-h)^2+k$

We have $f (x) = - 6 x^{2} - 5 x + 1$ $f(x)=-6x^2-5x+1$

= $- 6 (x^{2} + \frac{5}{6} x) + 1$ $-6(x^2+5/6x)+1$

= $- 6 (x^{2} + 2 \times \frac{5}{12} \times x + {(\frac{5}{12})}^{2}) - (- 6) \times {(\frac{5}{12})}^{2} + 1$ $-6(x^2+2xx5/12xx x+(5/12)^2)-(-6)xx(5/12)^2+1$

= $- 6 {(x + \frac{5}{12})}^{2} + \frac{25}{24} + 1$ $-6(x+5/12)^2+25/24+1$

= $- 6 {(x + \frac{5}{12})}^{2} + \frac{49}{24}$ $-6(x+5/12)^2+49/24$

and vertex is $(- \frac{5}{12}, - \frac{49}{24})$ $(-5/12,-49/24)$

graph{-6x^2-5x+1 [-3.8, 3, -1, 2.4]}

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How do you write $f (x) = - 6 x^{2} - 5 x + 1$ $f(x)=-6x^2-5x+1$ in vertex form?

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Explanation:

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How do you write f(x)=−6x2−5x+1f(x)=-6x^2-5x+1 in vertex form?

1 Answer

Explanation:

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How do you write $f (x) = - 6 x^{2} - 5 x + 1$ $f(x)=-6x^2-5x+1$ in vertex form?