How do you write $f (x) = - x^{2} + 10 x$ $f(x)= -x^2+10x$ into vertex form?

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Answer 1 · 2016-03-27T15:42:11

In vertex form we have that

$f (x) = - (x^{2} - 10 x + 25) + 25 \Rightarrow f (x) = - {(x - 5)}^{2} + 25$ $f(x)=-(x^2-10x+25)+25=>f(x)=-(x-5)^2+25$

Hence the vertex form is $f (x) = a \cdot {(x - h)}^{2} + k$ $f(x)=a*(x-h)^2+k$

we have that $a = - 1$ $a=-1$ , $h = 5$ $h=5$ , $k = 25$ $k=25$

How do you write f(x)= -x^2+10x f(x)=−x2+10xf(x)= -x^2+10x into vertex form?