How do you write $f(x) = x^2 - 3x + 1$ in vertex form?

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Answer 1 · 2016-05-13T11:13:25

In vertex form $f(x)=(x-3/2)^2-5/4$ Vertex is $(3/2,-5/4)$

$f(x)=x^2-3x+1= (x^2-3x+9/4)-9/4+1=(x-3/2)^2-5/4$ Vertex = $(3/2,-5/4)$ graph{x^2-3x+1 [-10, 10, -5, 5]}[Ans]

How do you write f(x) = x^2 - 3x + 1 f(x) = x^2 - 3x + 1 in vertex form?