How do you write f(x) = x^2 - 3x + 2f(x)=x2−3x+2 into vertex form?

1 Answer
Alan P.
May 28, 2015

The vertex form of a parabolic equation is of the form:
f(x) = (x-a)^2 +bf(x)=(x−a)2+b where the vertex is located at (a,b)(a,b)

Conversion of a parabolic equation to vertex form usually involves completion of the square methods.

Given f(x) = x^2-3x+2f(x)=x2−3x+2

f(x) = x^2-3x+(3/2)^2 + 2 -(3/2)^2f(x)=x2−3x+(32)2+2−(32)2

= (x-3/2)^2 -1/4=(x−32)2−14
or in complete vertex form
=(x-3/2)^2 + (-1/4)=(x−32)2+(−14) with the vertex at (3/2, -1/4)(32,−14)

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