Question

How do you write `f(x) = x^2 - 3x + 2` into vertex form?

Answer 1

The vertex form of a parabolic equation is of the form:
`f(x) = (x-a)^2 +b` where the vertex is located at `(a,b)`

Conversion of a parabolic equation to vertex form usually involves completion of the square methods.

Given `f(x) = x^2-3x+2`

`f(x) = x^2-3x+(3/2)^2 + 2 -(3/2)^2`

`= (x-3/2)^2 -1/4`
or in complete vertex form
`=(x-3/2)^2 + (-1/4)` with the vertex at `(3/2, -1/4)`