How do you write f(x) = x^2 - 4x - 10 in vertex form?

1 Answer
Apr 8, 2018

f(x)=(x-2)^2-14

Explanation:

"the equation of a parabola in "color(blue)"vertex form" is.

color(red)(bar(ul(|color(white)(2/2)color(black)(f(x)=a(x-h)^2+k)color(white)(2/2)|)))

"where "(h,k)" are the coordinates of the vertex and a is "
"a multiplier"

"to obtain this form "color(blue)"complete the square"

• " the coefficient of the "x^2" term must be 1 which it is"

• " add/subtract "(1/2"coefficient of the x-term")^2" to"
x^2-4x

rArrf(x)=x^2+2(-2)xcolor(red)(+4)color(red)(-4)-10

color(white)(rArrf(x))=(x-2)^2-14larrcolor(red)"in vertex form"