How do you write f(x)=x^2-6x+14 in vertex form?

2 Answers
bp
Aug 9, 2016

y-5= (x-3)^2

Explanation:

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Nghi N.
Aug 9, 2016

y = (x - 3)^2 + 5

Explanation:

General vertex form, if (xV) is the x- coordinate of vertex
y = a(x - xV)^2 + y(xV)
x-coordinate of vertex:
xV = -b/(2a) = 6/2 = 3
y-coordinate of vertex:
y(xV= 3) = 9 - 18 + 14 = 5
Vertex (3, 5)
Vertex form of y:
y = (x - 3)^2 + 5

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