How do you write $f (x) = x^{2} + 8 x + 10$ $f(x) = x^2 +8x + 10$ into vertex form?

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How do you write $f (x) = x^{2} + 8 x + 10$ $f(x) = x^2 +8x + 10$ into vertex form?

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Answer 1 · 2016-07-04T02:58:40

$f (x) = {(x + 4)}^{2} - 6$ $f(x) = (x + 4)^2 - 6$

Explanation:

$f (x) = x^{2} + 8 x + 10$ $f(x) = x^2 + 8x + 10$
x-coordinate of vertex:
$x = - \frac{b}{2 a} = - \frac{8}{2} = - 4$ $x = -b/(2a) = -8/2 = - 4$
y-coordinate of vertex:
$y (- 4) = 16 - 32 + 10 = - 6$ $y(-4) = 16 - 32 + 10 = -6$
Vertex form:
$f (x) = {(x + 4)}^{2} - 6$ $f(x) = (x + 4)^2 - 6$

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How do you write $f (x) = x^{2} + 8 x + 10$ $f(x) = x^2 +8x + 10$ into vertex form?

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How do you write f(x) = x^2 +8x + 10f(x)=x2+8x+10f(x) = x^2 +8x + 10 into vertex form?

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How do you write $f (x) = x^{2} + 8 x + 10$ $f(x) = x^2 +8x + 10$ into vertex form?