How do you write in standard form an equation of the line passing through the given point (-3,3) with the given slope 1?

Question

2397 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-01T19:24:18

Answer: $x - y + 6 = 0$

Why?

Use the general standard form:
$ax + by + c = 0$

Step1:
in gradient and one point form (also known as point-slope form) you have,
$y - 3 = 1*(x + 3)$

Step2:
arranging this you get,
$x - y + 6 = 0$

Answer 2 · 2015-04-01T19:32:43

$-x+y=0$

Since $y=mx+n$ can represent any line, we can use it.

$m$ is the slope of our line. The given slope is $1$ so $m=1$ .

So our formula is formed as $y=1*x+n$

We can now plug the point to this formula to find the value of $n$

$3=1*(-3)+n$
$n=6$

So $y=x+6$ represents the line. But we should reform this equality in order to be in the standart form:

$-x+y=6$ is the standart form ( $ax+by=c$ )