How do you write #root4(16^3)# as a fractional exponent? Prealgebra Exponents, Radicals and Scientific Notation Exponents 1 Answer Shwetank Mauria May 30, 2017 #root(4)(16^3)=8# Explanation: As #root(n)a=a^(1/n)# and #(a^m)^(1/n)=a^((mxx1/n))=a^(m/n)# #root(4)(16^3)=(16^3)^(1/4)=((2^4)^3)^(1/4)=2^((4xx3)/4)# = #2^(12/4)=2^3=8# Answer link Related questions How do you simplify #c^3v^9c^-1c^0#? How do you simplify #(- 1/5)^-2 + (-2)^-2#? How do you simplify #(4^6)^2 #? How do you simplify #3x^(2/3) y^(3/4) (2x^(5/3) y^(1/2))^3 #? How do you simplify #4^3ยท4^5#? How do you simplify #(5^-2)^-3#? How do you simplify and write #(-5.3)^0# with positive exponents? How do you factor #12j^2k - 36j^6k^6 + 12j^2#? How do you simplify the expression #2^5/(2^3 times 2^8)#? When can I add exponents? See all questions in Exponents Impact of this question 1996 views around the world You can reuse this answer Creative Commons License