How do you write the equation in slope intercept form given $6x - 2y = 12$ ?

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Answer 1 · 2016-02-22T12:03:00

Equation in slope intercept form is $y=3x-6$ .

Slope intercept form of a linear equation is $y=mx+c$ , where $m$ is the slope of the line and $c$ is intercept on $y$ axis.

For converting the linear equation $6x−2y=12$ in slope intercept form, we have to transpose terms to get te value of $y$ .

Hence, we transpose term containing $x$ to RHS, which makes it

$-2y=-6x+12$ and for getting value of $y$ , let us divide both sides by $-2$ and equation becomes

$y=(-6)/(-2)x+12/(-2)$ or $y=3x-6$

Hence equation in slope intercept form is $y=3x-6$ .

How do you write the equation in slope intercept form given 6x - 2y = 126x - 2y = 12?