How do you write the equation of the parabola in vertex form given vertex (0,0) and a focus (-3,0)?

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Answer 1 · 2017-03-14T06:45:29

The equation of the parabola is #y^2=-6x#

The equation of a parabola with the vertex at #(0,0)# and the axis on the x-axis is

#y^2=-2px#

The focus is #F=(-p/2,0)=(-3,0)#

Therefore,

#-p/2=-3#

#p=6#

The equation of the parabola is

#y^2=-6x#

graph{(y^2+6x)((x+3)^2+(y)^2-0.01)=0 [-8.89, 8.89, -4.445, 4.44]}