Question

How do you write the equation of the quadratic function with roots 0 and 1 and a vertex at (-1/2, 2)?

Answer 1

The function is: `y=8/3x^2-8/3x`.

Assuming you are looking for a function `f(x)=ax^2+bx+c`, you can find the equation by solving the following sysyem of equations:

`{(f(0)=0),(f(1)=0),(f(-1/2)=2):}`

which leads to:

`{(c=0),(a+b=0),(1/4a-1/2b=0):}`