How do you write the expression 3*3*x*x*x*x3⋅3⋅x⋅x⋅x⋅x using exponents? Prealgebra Exponents, Radicals and Scientific Notation Exponents 1 Answer Barney V. Jan 4, 2017 3^2x^432x4 Explanation: 3*3= 3^23⋅3=32 x*x*x*x=x^4x⋅x⋅x⋅x=x4 = 3^2x^4=32x4 Answer link Related questions How do you simplify c^3v^9c^-1c^0c3v9c−1c0? How do you simplify (- 1/5)^-2 + (-2)^-2(−15)−2+(−2)−2? How do you simplify (4^6)^2 (46)2? How do you simplify 3x^(2/3) y^(3/4) (2x^(5/3) y^(1/2))^3 3x23y34(2x53y12)3? How do you simplify 4^3·4^543⋅45? How do you simplify (5^-2)^-3(5−2)−3? How do you simplify and write (-5.3)^0(−5.3)0 with positive exponents? How do you factor 12j^2k - 36j^6k^6 + 12j^212j2k−36j6k6+12j2? How do you simplify the expression 2^5/(2^3 times 2^8)2523×28? When can I add exponents? See all questions in Exponents Impact of this question 2177 views around the world You can reuse this answer Creative Commons License