How do you write the function in standard form $y = \frac{1}{2} {(8 x - 1)}^{2} - \frac{3}{2}$ $y=1/2(8x-1)^2-3/2$ ?

Question

How do you write the function in standard form $y = \frac{1}{2} {(8 x - 1)}^{2} - \frac{3}{2}$ $y=1/2(8x-1)^2-3/2$ ?

1 Answer

Impact of this question

1713 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-01-09T08:14:45

$y = 32 x^{2} - 8 x - 1$ $y=32x^2-8x-1$

Explanation:

$the equation of a parabola in standard form$ $"the equation of a parabola in "color(blue)"standard form"$ is.

$∙ x y = a x^{2} + b x + c x; a \neq 0$ $•color(white)(x)y=ax^2+bx+c color(white)(x);a!=0$

$expand the factor {(8 x - 1)}^{2} using FOIL$ $"expand the factor "(8x-1)^2" using FOIL"$

$y = \frac{1}{2} (64 x^{2} - 16 x + 1) - \frac{3}{2}$ $y=1/2(64x^2-16x+1)-3/2$

$distribute the bracket$ $"distribute the bracket"$

$y = 32 x^{2} - 8 x + \frac{1}{2} - \frac{3}{2}$ $y=32x^2-8x+1/2-3/2$

$y = 32 x^{2} - 8 x - 1 \leftarrow in standard form$ $color(white)(y)=32x^2-8x-1larrcolor(red)"in standard form"$

Science

Math

Humanities

... and beyond

How do you write the function in standard form $y = \frac{1}{2} {(8 x - 1)}^{2} - \frac{3}{2}$ $y=1/2(8x-1)^2-3/2$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you write the function in standard form y=1/2(8x-1)^2-3/2y=12(8x−1)2−32y=1/2(8x-1)^2-3/2?

1 Answer

Explanation:

Related questions

Impact of this question

How do you write the function in standard form $y = \frac{1}{2} {(8 x - 1)}^{2} - \frac{3}{2}$ $y=1/2(8x-1)^2-3/2$ ?