How do you write the function in standard form $y = {(x + 3)}^{2} + 2$ $y=(x+3)^2+2$ ?

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Answer 1 · 2018-06-06T13:26:56

$y = x^{2} + 6 x + 11$ $y=x^2+6x+11$

Expanding we get
$y = x^{2} + 6 x + 9 + 2 = x^{2} + 6 x + 11$ $y=x^2+6x+9+2=x^2+6x+11$

How do you write the function in standard form y=(x+3)^2+2y=(x+3)2+2y=(x+3)^2+2?