How do you write the quadratic in vertex form given $y=2x^2-10x+5$ ?

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Answer 1 · 2015-05-09T03:02:23

Vertex form $f(x) = (x - b/(2a))^2 + f(-b/(2a))$

$-b/2a = 10/4 = 5/2$
$f(5/4) = 2(25/4) - 10(5/2) + 5 = -15/2$

Vertex form $f(x) = (x - 5/2)^2 - 15/2$

How do you write the quadratic in vertex form given y=2x^2-10x+5y=2x^2-10x+5?