How do you write the quadratic in vertex form given $y=3x^2+6x-1$ ?

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Answer 1 · 2015-05-09T19:45:19

The vertex form is:

$y-y_v=a(x-x_v)^2$ .

So:

$y=3(x^2+2x)-1rArry=3(x^2+2x+1-1)-1rArr$

$y=3(x^2+2x+1)-3-1rArry=3(x+1)^2-4rArr$

$y+4=3(x+1)^2$ .

How do you write the quadratic in vertex form given y=3x^2+6x-1y=3x^2+6x-1?