How do you write the quadratic in vertex form given $y= x^2 - 12x + 20$ ?

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Answer 1 · 2015-05-13T02:59:15

$(-b/2a) = -12/2 = 6$

$f(-b/2a) = f(6) = 36 - 72 + 20 = -16$

Factored form: $f(x) = (x - 6)^2 - 16$

Check:
$Develop f(x) = (x^2 - 12x + 36 - 16 = x^2 - 12x + 20$ . Correct

How do you write the quadratic in vertex form given y= x^2 - 12x + 20 y= x^2 - 12x + 20 ?