How do you write the quadratic in vertex form given $y = x^{2} + 4 x - 7$ $y=x^2+4x-7$ ?

Question

How do you write the quadratic in vertex form given $y = x^{2} + 4 x - 7$ $y=x^2+4x-7$ ?

1 Answer

Impact of this question

2259 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-10T16:20:28

$y = x^{2} + 4 x - 7 = {(x + 2)}^{2} - 11$ $y = x^2+4x-7 = (x+2)^2 - 11$

In general, for $y = a x^{2} + b x + c$ $y = ax^2 + bx + c$ , the $x$ $x$ coordinate of the vertex is $- \frac{b}{2 a}$ $-b/(2a)$ , and the vertex form is:

$y = a {(x + \frac{b}{2 a})}^{2} + (c - \frac{b^{2}}{4 a})$ $y = a(x + b/(2a))^2 + (c - b^2/(4a))$

Science

Math

Humanities

... and beyond

How do you write the quadratic in vertex form given $y = x^{2} + 4 x - 7$ $y=x^2+4x-7$ ?

1 Answer

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you write the quadratic in vertex form given y=x2+4x−7y=x^2+4x-7?

1 Answer

Related questions

Impact of this question

How do you write the quadratic in vertex form given $y = x^{2} + 4 x - 7$ $y=x^2+4x-7$ ?