How do you write the quadratic in vertex form given $y= x^2-6x+15$ ?

Question

2153 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-25T18:13:23

Vertex form is written by completing the square in the equation. Here y= $x^2 -6x+15$

= $x^2 -6x +9 -9 +15$ { Half the coefficent of x and square it, then add and subtract that number]

= $(x-3)^2 +6$

The equation is therefore y-6= $(x-3)^2$ which is in the required format. Vertex is (3,6)

How do you write the quadratic in vertex form given y= x^2-6x+15y= x^2-6x+15?