How do you write the quadratic in vertex form given y=−x2+6x−5?

1 Answer
Don't Memorise
Apr 29, 2015

The vertex form of a quadratic function is given by
y=a(x−h)2+k, where (h,k) is the vertex of the parabola.

We can use the process of Completing the Square to get this into the Vertex Form.

y=−x2+6x−5

→y+5=−x2+6x (Transposed -5 to the Left Hand Side)

→y+5=−1(x2−6x) (Made the coefficient of x2 as 1)

Now we subtract 9 from each side to complete the square

→y+5−9=−1(x2−6x+32)

→y−4=−1(x−3)2

→y=−(x−3)2+4 is the Vertex Form

The vertex of the Parabola is{3,4}

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