Question

How do you write the slope of the line tangent to `g(x)=3/2x+1` at the point (-2,2)?

Answer 1

`3/2`

Explanation:

`g(x)` is a straight line and comparing with the standard equation `y=mx+c` we see that `m=3/2`, so the gradient of the tangent is constant and is `3/2` everywhere on `g`