Question

How do you write the slope of the line tangent to `g(x)=5-x^2` at the point (2,1)?

Answer 1

`-4`

Explanation:

`g(2) = 1`

`g'(x) = -2x => g'(2) = -4`

The end.

`y = ax + b, a = -4, y(2) = 1`

`1 = -4 * 2 + b => b = 9`

`y = -4x + 9`