How do you write $x = 1/3 y – 2/3$ in standard form?

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Answer 1 · 2018-04-15T09:11:17

See a solution process below..

The standard form formula goes like this;

$Ax + Bx = C$

Where;

$A, B and C$ are coefficients..

$x = 1/3y - 2/3$

First, multiply through by their LCM, in this case is $3$

$3(x) = 3(1/3y) - 3(2/3)$

$3x = 3y -2$

$3x - 3y = -2, "is in standard form"$

How do you write x = 1/3 y – 2/3 x = 1/3 y – 2/3 in standard form?