How do you write #(x^2 + x + 2) + (3x^2 - 2x + 10)# in standard form?

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Answer 1 · 2016-05-31T05:41:40

#= 4*x²-x+12#

#= 4*x²-x+12#

Answer 2 · 2016-05-31T11:14:30

#" "4x^2-x+12#

As there is a + between the brackets so multiply the contents of the 2nd bracket by +1 giving:

#" "x^2+x+2" "+" "3x^2-2x+10#

Collecting like terms

#" "( x^2+3x^2)+(x-2x)+(2+10)#
The purpose of the above brackets is to make things clearer about what is happening. They serve no other purpose.

#" "4x^2-x+12#

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Note that #+(x-2x)# is the same as #+(-x)#
where #+" and "- " give us "-#

so #+(-x)=-x#
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