How do you write $(x - 3) (x + 2) (x + 5)$ $(x-3)(x+2)(x+5)$ in standard form?

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How do you write $(x - 3) (x + 2) (x + 5)$ $(x-3)(x+2)(x+5)$ in standard form?

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Answer 1 · 2015-10-03T16:38:21

Think distributivity (aka rainbow method)

Explanation:

$(x - 3) (x + 2) (x + 5)$ $(x-3)(x+2)(x+5)$
$= (x^{2} + 2 x - 3 x - 6) (x + 5)$ $=(x^2+2x-3x-6)(x+5)$
$= (x^{2} - x - 6) (x + 5)$ $=(x^2-x-6)(x+5)$
$= x^{3} + 5 x^{2} - x^{2} - 5 x - 6 x - 30$ $=x^3+5x^2-x^2-5x-6x-30$
$= x^{3} + 4 x^{2} - 11 x - 30$ $=x^3+4x^2-11x-30$

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How do you write $(x - 3) (x + 2) (x + 5)$ $(x-3)(x+2)(x+5)$ in standard form?

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How do you write $(x - 3) (x + 2) (x + 5)$ $(x-3)(x+2)(x+5)$ in standard form?