How do you write $y= -0.015x^2+1.501x-17.157$ into vertex form?

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Answer 1 · 2015-06-10T22:48:05

Vertex form of y.

x of vertex: $x = (-b/2a) = -1.501/-0.03= 50$

y of vertex: y = f(50) = - 0.015(2500) + 1.501(50) - 17.157

= - 37.5 + 75.01 - 17.157 = 20.39

Vertex form: $y = - 0.015(x -50)^2 - 20.39$

How do you write y= -0.015x^2+1.501x-17.157y= -0.015x^2+1.501x-17.157 into vertex form?