How do you write $y = (\frac{1}{4}) x + (\frac{3}{4})$ $y=(1/4)x+(3/4)$ in standard form?

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Answer 1 · 2015-07-05T07:10:03

Multiply both sides times 4. Move the x and y terms to the left side. Multiply both sides times -1.

Standard form for a linear equation is $A x + B y = C$ $"A"x+"B"y="C"$ .

$y = \frac{1}{4} x + \frac{3}{4}$ $y=1/4x+3/4$

Multiply both sides of the equation by $4$ $4$ .

$4 y = x + 3$ $4y=x+3$

Subtract $x$ $x$ from both sides.

$- x + 4 y = 3$ $-x+4y=3$

Multiply both sides times $- 1$ $-1$ .

$x - 4 y = - 3$ $x-4y=-3$

How do you write y=(1/4)x+(3/4)y=(14)x+(34)y=(1/4)x+(3/4) in standard form?