How do you write $y + 11 = \frac{1}{3} (x + 3)$ $y + 11 =1/3 (x + 3)$ in standard form?

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Answer 1 · 2017-04-13T13:38:02

$y = (\frac{x}{3}) - 10$ $y=(x/3)-10$

When you arrange your equation:
$y = (\frac{x}{3}) + (\frac{3}{3}) - 11$ $y=(x/3)+(3/3)-11$
$= (\frac{x}{3}) - 10$ $=(x/3)-10$

This isyour equation: $y = (\frac{x}{3}) - 10$ $y=(x/3)-10$ or
$y = \frac{x - 30}{3}$ $y=(x-30)/3$

How do you write y + 11 =1/3 (x + 3)y+11=13(x+3)y + 11 =1/3 (x + 3) in standard form?