How do you write $y-2=4(x-3)$ in slope intercept form?

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Answer 1 · 2017-01-12T14:02:37

See the process for answer this question below:

The slope-intercept form of a linear equation is:

$y = color(red)(m)x + color(blue)(b)$

Where $color(red)(m)$ is the slope and $color(blue)(b$ is the y-intercept value.

Therefore, in order to transform this equation from point-slope form to slope-intercept form we must solve for $y$ :

$y - 2 = (4 xx x) - (4 xx 3)$

$y - 2 = 4x - 12$

$y - 2 + color(red)(2) = 4x - 12 + color(red)(2)$

$y - 0 = 4x - 10$

$y = 4x - 10$

$y = color(red)(4)x + color(blue)(10)$

How do you write y-2=4(x-3)y-2=4(x-3) in slope intercept form?