How do you write $y=-2.5(x-1.3)(x+5.2)$ in standard form?

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Answer 1 · 2018-03-31T08:07:47

$y = -2.5x^2 - 9.75x + 16.9$

The standard form of parabola: $y = ax^2 + bx + c$

$y = -2.5(x - 1.3)(x + 5.2)$

#y = -2.5 (x^2+ 5.2x - 1.3x - 6.76)

$y = -2.5x^2 - 9.75x + 16.9$

How do you write y=-2.5(x-1.3)(x+5.2)y=-2.5(x-1.3)(x+5.2) in standard form?