How do you write $y = - 2 (x + 4) (x + 1)$ $y = -2(x+4)(x+1)$ in standard form?

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Answer 1 · 2018-04-18T17:51:43

Using FOIL, we get $y = - 2 x^{2} - 10 - 8 .$ $y = -2x^2 - 10 - 8.$

$y = - 2 (x + 4) (x + 1)$ $y = -2(x+4)(x+1)$

Using FOIL:

$y = - 2 (x^{2} + x + 4 x + 4)$ $y = -2 (x^2 + x + 4x + 4)$

$y = - 2 x^{2} - 10 x - 8$ $y = -2 x^2 - 10 x - 8$

That's standard form so we stop.

How do you write y = -2(x+4)(x+1)y=−2(x+4)(x+1)y = -2(x+4)(x+1) in standard form?