How do you write $y = - 2 (x - 9) (x + 7)$ $y = -2(x-9)(x+7)$ in standard form?

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How do you write $y = - 2 (x - 9) (x + 7)$ $y = -2(x-9)(x+7)$ in standard form?

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Answer 1 · 2016-07-24T22:26:28

$y = - 2 (x^{2} - 2 x + 63)$ $y = -2(x^2 - 2x + 63)$

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$y = - 2 (x - 9) (x + 7) = - 2 (x^{2} - 2 x + 63)$ $y = -2(x - 9)(x + 7) = - 2(x^2 - 2x + 63)$
$y = - 2 x^{2} + 4 x - 126$ $y = -2x^2 + 4x - 126$

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How do you write $y = - 2 (x - 9) (x + 7)$ $y = -2(x-9)(x+7)$ in standard form?

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How do you write y=−2(x−9)(x+7)y = -2(x-9)(x+7) in standard form?

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How do you write $y = - 2 (x - 9) (x + 7)$ $y = -2(x-9)(x+7)$ in standard form?