How do you write $y = - 2 x^{2} - 12 x - 23$ $y=-2x^2-12x-23$ in vertex form?

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Answer 1 · 2016-11-14T07:50:28

The vertex form is $y = - 2 {(x + 3)}^{2} - 5$ $y=-2(x+3)^2-5$

Let's complete the squares

$y = - 2 x^{2} - 12 x - 23$ $y=-2x^2-12x-23$

$y = - 2 (x^{2} + 6 x) - 23$ $y=-2(x^2+6x)-23$

$y = - 2 (x^{2} + 6 x + 9) - 23 + 18$ $y=-2(x^2+6x+9)-23+18$

$y = - 2 {(x + 3)}^{2} - 5$ $y=-2(x+3)^2-5$

This is the vertex form

The vertex is $= (- 3, - 5)$ $=(-3,-5)$

The axis of symmetry is $x = - 3$ $x=-3$

graph{-2x^2-12x-23 [-26.29, 19.32, -13.57, 9.25]}

How do you write y=-2x^2-12x-23y=−2x2−12x−23y=-2x^2-12x-23 in vertex form?