How do you write #y=-2x^2-12x-23# in vertex form?

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Answer 1 · 2016-11-14T07:50:28

The vertex form is #y=-2(x+3)^2-5#

Let's complete the squares

#y=-2x^2-12x-23#

#y=-2(x^2+6x)-23#

#y=-2(x^2+6x+9)-23+18#

#y=-2(x+3)^2-5#

This is the vertex form

The vertex is #=(-3,-5)#

The axis of symmetry is #x=-3#

graph{-2x^2-12x-23 [-26.29, 19.32, -13.57, 9.25]}