How do you write $y = 2 x^{2} - 8 x + 13$ $y= 2x^2 - 8x + 13$ into vertex form?

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Answer 1 · 2015-05-22T14:24:23

Vertex form for a quadratic is
$y = m (x - a) + b$ $y = m(x-a) +b$ where the vertex is $(a, b)$ $(a,b)$

Given $y = 2 x^{2} - 8 x + 13$ $y=2x^2-8x+13$

Extract $m$ $m$

$y = 2 (x^{2} - 4 x) + 13$ $y= 2(x^2-4x) + 13$

Complete the square

$y = 2 (x^{2} - 4 x + 4) + 13 + 8$ $y= 2(x^2-4x+4) + 13 +8$

Complete writing in vertex form

$y = 2 {(x - 2)}^{2} + 21$ $y = 2(x-2)^2 +21$

How do you write y=2x2−8x+13y= 2x^2 - 8x + 13 into vertex form?