How do you write $y+3=-1/3(2x+6)$ in slope intercept form?

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Answer 1 · 2017-04-29T20:18:48

See the solution process below:

The slope-intercept form of a linear equation is: $y = color(red)(m)x + color(blue)(b)$

Where $color(red)(m)$ is the slope and $color(blue)(b)$ is the y-intercept value.

Solving this for $y$ gives:

$y + 3 = color(red)(-1/3)(2x + 6)$

$y + 3 = (color(red)(-1/3) * 2x) + (color(red)(-1/3) * 6)$

$y + 3 = -2/3x + (-6/3)$

$y + 3 = -2/3x - 6/3$

$y + 3 = -2/3x - 2$

$y + 3 - 3 = -2/3x - 2 - 3$

$y + 0 = -2/3x - 5$

$y = color(red)(-2/3)x - color(blue)(5)$

How do you write y+3=-1/3(2x+6)y+3=-1/3(2x+6) in slope intercept form?