How do you write $y=3-2x-x^2$ in vertex form?

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Answer 1 · 2017-06-14T10:09:37

Equation in vertex form is $y=-(x+1)^2+4$

$y= -x^2-2x+3 = -x^2-2x-1+1+3$

$= -(x^2+2x+1)+4= -(x+1)^2+4$ .

Comparing with vertex form of equation $y= a(x-h)^2+k ; (h,k)$ being vertex . Here $h=-1 , k=4$

So vertex is at $(-1,4)$
Equation in vertex form is $y=-(x+1)^2+4$
graph{-x^2-2x+3 [-10, 10, -5, 5]} [Ans]

How do you write y=3-2x-x^2y=3-2x-x^2 in vertex form?