How do you write #y=-3/4x+5/2# in standard form?

1 Answer
Jun 9, 2018

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Linear Equation in Standard Form : #color(blue)(3x+4y=10#

Explanation:

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You are given a Linear Equation : #color(red)(y=-3/4x+5/2#

The Standard Form for a linear equation in two variables, #x# and #y#, is

#color(green)(Ax+By=C#, where

#color(green)(A, B and C# are all integer values.

Consider the given Linear Equation : #color(red)(y=-3/4x+5/2#

Multiply both sides of the equation by 4

#=>4*y=4[-3/4x+5/2]#

#rArr 4y=-4(3/4)x+4(5/2)#

#rArr 4y=-cancel 4(3/cancel 4)x+cancel 4^color(red)(2)(5/cancel 2)#

#rArr 4y=-3x+(2)(5)#

#rArr 4y=-3x+10#

Move the term #3x# to the left hand side of the equation by adding #3x# to both sides.

#rArr 4y+3x=-3x+10+3x#

#rArr 4y+3x=-cancel (3x)+10+cancel(3x)#

Rearrange the terms on the left hand side to bring the equation to the Standard Form.

#3x+4y=10#

Hence, #color(blue)(4x+3y=10# is the required equation in Standard Form.

Hope you find the solution process helpful.