How do you write $y = 3(x+1)^2 - 27$ in standard form?

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Answer 1 · 2016-05-07T21:40:01

Really, you could just expand it out.

$(x+1)^2 = (x+1)(x+1) = x^2 + 2x + 1$

$y = 3(x^2 + 2x + 1) - 27$

$y = 3x^2 + 6x + 3 - 27$

$y = 3x^2 + 6x - 24$

How do you write y = 3(x+1)^2 - 27y = 3(x+1)^2 - 27 in standard form?