How do you write $y=3x^2-12x+1$ in vertex form?

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Answer 1 · 2018-04-21T05:07:46

Given -

$y=3x^2-12x+1$

$x=(-b)/(2a)=(-(-12))/(2xx3)=12/6=2$

At $(x=2)$

$y=3(2^2)$ -12(2)+1=12-24+1=-11

Vertex $(2,-11)$

The vertex form is -

$y=a(x-h)^2+k$

Where -

$a=3$ is the coefficient of $x^2$
$h=2$ is the x - co-ordinate of vertex
$k=-11$ is the y - co-ordinate of vertex

$y=3(x-2)^2-11$

How do you write y=3x^2-12x+1y=3x^2-12x+1 in vertex form?