How do you write $y + 4 = 3 (3 x + 3)$ $y+4=3(3x+3)$ in slope intercept form?

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Answer 1 · 2017-02-03T16:42:41

$y = 9 x + 5$ $y = color(red)(9)x + color(blue)(5)$

The slope-intercept form of a linear equation is:

$y = m x + b$ $y = color(red)(m)x + color(blue)(b)$

Where $m$ $color(red)(m)$ is the slope and $b$ $color(blue)(b)$ is the y-intercept value.

Solving for $y$ $y$ gives:

$y + 4 = (3 \times 3 x) + (3 \times 3)$ $y + 4 = (3 xx 3x) + (3 xx 3)$

$y + 4 = 9 x + 9$ $y + 4 = 9x + 9$

$y + 4 - 4 = 9 x + 9 - 4$ $y + 4 - color(red)(4) = 9x + 9 - color(red)(4)$

$y + 0 = 9 x + 5$ $y + 0 = 9x + 5$

$y = 9 x + 5$ $y = 9x + 5$

How do you write y+4=3(3x+3)y+4=3(3x+3)y+4=3(3x+3) in slope intercept form?