How do you write #y = 4(x-1)^2-10# into standard form?

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Answer 1 · 2015-05-01T14:42:15

Multiply it out and simplify (combine like terms) putting the terms in decreasing order of exponents.

#y = 4(x-1)^2-10#
For the order of operations, we need to square before we multiply by #4#

If you need to work out #(x-1)^2# in the margin, or on extra paper, do so.
#(x-1)^2 = (x-1)(x-1) = x^2 - x - x +1 = x^2-2x+1#

#y = 4(x-1)^2-10#

#y = 4(x^2-2x+1)-10#

#y = 4x^2-8x+ 4 -10#

#y = 4x^2-8x - 6#

And that's it. We are finished.