How do you write $y = 4(x-1)^2-10$ into standard form?

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Answer 1 · 2015-05-01T14:42:15

Multiply it out and simplify (combine like terms) putting the terms in decreasing order of exponents.

$y = 4(x-1)^2-10$
For the order of operations, we need to square before we multiply by $4$

If you need to work out $(x-1)^2$ in the margin, or on extra paper, do so.
$(x-1)^2 = (x-1)(x-1) = x^2 - x - x +1 = x^2-2x+1$

$y = 4(x-1)^2-10$

$y = 4(x^2-2x+1)-10$

$y = 4x^2-8x+ 4 -10$

$y = 4x^2-8x - 6$

And that's it. We are finished.

How do you write y = 4(x-1)^2-10y = 4(x-1)^2-10 into standard form?