Question

How do you write `y=4(x+3/2)(3/4x+1/4)` in standard form?

Answer 1

`3x^2+11/2x+3/2=0`

Explanation:

First I would use the distributive law to expand the brackets, but for now ignore the 4.

So it becomes:
`4(3/4x^2+1/4x+9/8x+3/8)`

Then simplify everything in he brackets to become:
`4(3/4x^2+11/8x+3/8)`

Then times all 3 terms by 4, so it becomes:
`3x^2+11/2x+3/2`

Then simply add `=0` to finish in standard form.
`3x^2+11/2x+3/2=0`