How do you write $y - 5 = \frac{3}{2} (x + 4)$ $y-5=3/2(x+4)$ in standard form?

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Answer 1 · 2015-05-27T11:28:51

Standard form for a linear equation is (normally)
$A x + B y = C$ $Ax+By = C$ with $A>=0 and AepsilonZZ$

Given $y-5 = 3/2(x+4)$

$rarr 2y-10 = 3x +12$

$rarr -3x + 2y = 22$

$rarr 3x -2y = -22$

which is in "standard form"

How do you write y-5=3/2(x+4) y−5=32(x+4)y-5=3/2(x+4) in standard form?