How do you write $y = x^{2} + 12 x + 32$ $y=x^2+12x+32$ into vertex form?

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Answer 1 · 2015-05-24T17:55:03

The vertex form is:

$y - y_{v} = a {(x - x_{v})}_{v}^{2}$ $y-y_v=a(x-x_v)^2$ .

So:

$y = x^{2} + 12 x + 32 \Rightarrow y = x^{2} + 12 x + 36 - 36 + 32 \Rightarrow$ $y=x^2+12x+32rArry=x^2+12x+36-36+32rArr$

$y = {(x + 6)}^{2} - 4 \Rightarrow y + 4 = {(x + 6)}^{2}$ $y=(x+6)^2-4rArry+4=(x+6)^2$ .

How do you write y=x^2+12x+32y=x2+12x+32y=x^2+12x+32 into vertex form?