How do you write $y = {(x - 2)}^{2} + 6$ $y=(x-2)^2+6$ ?

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Answer 1 · 2018-05-13T18:28:39

$y = x^{2} - 4 x + 12$ $y=x^2-4x+12$

The section is: Standard polynomial form.

$y = {(x - 2)}^{2} + 6$ $y=(x-2)^2+6$ is vertex form.

$y = (x - 2) (x - 2) + 6$ $y=color(blue)((x-2))color(green)( (x-2) )+6$

$y = x (x - 2) dd - 2 (x - 2) + 6$ $y=color(green)(color(blue)( x)(x-2 ) color(white)("dd")color(blue)( -2)(x-2 ))+6$

Notice the way the minus followed the 2color(white)("d")

$y = x^{2} - 2 x ddd - 2 x + 4 + 6$ $y=x^2-2xcolor(white)("ddd")-2x+4+6$

$y = x^{2} - 4 x + 12$ $y=x^2-4x+12$

How do you write y=(x-2)^2+6y=(x−2)2+6y=(x-2)^2+6?